Fail job on ganeti exceptions

When a Job raises a ganeti exception a message is printed but nothing is
reported in the job itself. It's better to update the job status, thus
notifying the client, possibly polling for the job result, of what went
wrong.

Reviewed-by: iustinp

daemons/ganeti-masterd

@@ -285,7 +285,9 @@ def PoolWorker(worker_id, incoming_queue):
       try:
         JobRunner(proc, item)
       except errors.GenericError, err:
-        print "ganeti exception %s" % err
+        msg = "ganeti exception %s" % err
+        item.SetStatus(opcodes.Job.STATUS_FAIL, result=[msg])
+        print msg
     finally:
       #utils.Unlock('cmd')
       #utils.LockCleanup()